Having a Little Fun at SQL Server Central
Steve reminisces on some of the fun times he's had at SQL Server Central.
2026-02-27
122 reads
Steve reminisces on some of the fun times he's had at SQL Server Central.
2026-02-27
122 reads
A look back at SQL Server Central after 25 years from founder Brian Knight.
2026-02-20
1,515 reads
Steve talks about some of the charitable work at SQL Server Central.
2026-02-20
106 reads
This is part of a few memories from the founders of SQL Server Central, celebrating 25 years of operation this month. When we started SQL Server Central, our goal was to build a great resource that helped other people advance in their careers and also made some money. Our decisions in building the site were […]
2026-02-13
128 reads
2026-02-06
164 reads
2026-02-02
225 reads
Casino Night from SQL Server Central is coming back to the PASS Data Community Summit.
2024-09-11
482 reads
SQL Server Central is changing their policy to respond to the increased use of AI technologies.
2024-02-02
400 reads
We are adding a consent form to the SQL Server Central website to allow our cookies.
2024-01-10
1,462 reads
The SQL Server Central database servers are being upgraded on Thursday, Nov 2.
2023-11-01
685 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
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WhatsApp CS 628218520154 Jl. Pegangsaan Timur No.1, Cikini, Kec. Menteng, Kota Jakarta Pusat, Daerah...
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I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers