As Robin points out there is no built in way to make sure users have strong passwords when using SQL authentication. There are a couple changes you can make (with appropriate warnings!) that will allow you to do this. Read on to find out why and how.
2004-03-02
6,702 reads
This script will display the defragmentation of table(s) all indexes of selected tables and display a table/list of the DBCC SHOWCONTIG. It will aslo will report if there are tables in the list that can't be found in the current database. Run the script in the database where the tables you want to check are.Check […]
2003-08-21
822 reads
Don't like the blackbox approach of maintenance plans? Like the maintenance plans but need a tweak to suit your needs? New author Robin Back has put together a monster script to allow you to build your own quickly and easily.
2003-08-20
9,842 reads
I manage quite a few hundred databases across the company. Time to time I get a question if I can check wheather a database is beeing used or not, and if it is, by whom?There are probably a 1000 ways to do this, but I've created a script for creating a scheduled job that runs […]
2003-07-15
2,694 reads
By Steve Jones
Here are the resources for my talk at Day of Data Boston. Slides –...
By Steve Jones
I’ve covered the values in a number of previous posts on the Book of...
By Arun Sirpal
When the evidence names the database, it says so. When it doesn’t, it stops....
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers